Integrabile

Test with accessible formulae

Which is the correct identity?

$\sqrt{2} + \sqrt{3} = \sqrt{5}$
$\sqrt{2} \cdot \sqrt{3} = \sqrt{6}$
$\frac{3}{6 + 9} = \frac{1}{2} + \frac{1}{3}$

Which is the wrong identity?

$(a + b)^{n} = \sum_{k = 0}^{n} (\binom{n}{k}) a^{k} b^{n - k}$
$lim_{n \to + \infty} \frac{1}{x} = + \infty$
$\int x d x = \frac{x^{2}}{2} + C, C \in R$

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